JEE MAIN - Mathematics (2021 - 18th March Morning Shift - No. 18)
The missing value in the following figure is
_18th_March_Morning_Shift_en_18_1.png)
Answer
4
Explanation
Inside number $=\left(\right.$ difference)${ }^{(\text {difference}) !}$
$=($Greater number - Smaller number)(Greater number - Smaller number)!
i.e. $1=(2-1)^{(2-1) !}, $
$4^{24}=(12-8)^{(12-8) !}, $
$3^6=(7-4)^{(7-4) !}$
$\therefore \quad ?=(5-3)^{(5-3) !}$
$\therefore$ Required number $=2^{2 !}=2^{2 \times 1}=4$
$=($Greater number - Smaller number)(Greater number - Smaller number)!
i.e. $1=(2-1)^{(2-1) !}, $
$4^{24}=(12-8)^{(12-8) !}, $
$3^6=(7-4)^{(7-4) !}$
$\therefore \quad ?=(5-3)^{(5-3) !}$
$\therefore$ Required number $=2^{2 !}=2^{2 \times 1}=4$
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