JEE MAIN - Mathematics (2021 - 17th March Evening Shift - No. 1)
If the sides AB, BC and CA of a triangle ABC have 3, 5 and 6 interior points respectively, then the total number of triangles that can be constructed using these points as vertices, is equal to :
240
360
333
364
Explanation
_17th_March_Evening_Shift_en_1_1.png)
Total number of triangles
= $${}^{14}{C_3} - {}^3{C_3} - {}^5{C_3} - {}^6{C_3}$$
= 364 – 31 = 333
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