JEE MAIN - Mathematics (2020 - 9th January Evening Slot - No. 10)
If A = {x $$ \in $$ R : |x| < 2} and B = {x $$ \in $$ R : |x – 2| $$ \ge $$ 3};
then :
A – B = [–1, 2)
A $$ \cup $$ B = R – (2, 5)
A $$ \cap $$ B = (–2, –1)
B – A = R – (–2, 5)
Explanation
A : x $$ \in $$ (–2, 2);
B : x $$ \in $$ (–$$\infty $$, –1] $$ \cup $$ [5, $$\infty $$)
$$ \Rightarrow $$ B – A = R – (–2, 5)
_9th_January_Evening_Slot_en_10_1.png)
B : x $$ \in $$ (–$$\infty $$, –1] $$ \cup $$ [5, $$\infty $$)
$$ \Rightarrow $$ B – A = R – (–2, 5)
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