JEE MAIN - Mathematics (2020 - 6th September Morning Slot - No. 16)
A ray of light coming from the point (2, $$2\sqrt 3 $$) is incident at an angle 30o on the line x = 1 at the
point A. The ray gets reflected on the line x = 1 and meets x-axis at the point B. Then, the line AB
passes through the point :
(3, -$$\sqrt 3 $$)
(4, -$$\sqrt 3 $$)
$$\left( {4, - {{\sqrt 3 } \over 2}} \right)$$
$$\left( {3, - {1 \over {\sqrt 3 }}} \right)$$
Explanation
_6th_September_Morning_Slot_en_16_1.png)
Equation of reflected Ray P'B :
y - 2$$\sqrt 3 $$ = tan 120o (x - 0)
$$ \Rightarrow $$ $$\sqrt 3 $$x + y = 2$$\sqrt 3 $$
(3, -$$\sqrt 3 $$) satisfy the line.
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