JEE MAIN - Mathematics (2020 - 4th September Morning Slot - No. 7)
Two vertical poles AB = 15 m and CD = 10 m are standing apart on a horizontal ground with points A
and C on the ground. If P is the point of intersection of BC and AD, then the height of P (in m)
above the line AC is :
10/3
5
20/3
6
Explanation
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Equation of AD : $$y = {{10} \over a}x$$
Equation of BC : $${x \over a} + {y \over {15}} = 1$$
$$ \Rightarrow {{ay} \over {10a}} + {y \over {15}} = 1$$
$$ \Rightarrow {{3y + 2y} \over {30}} = 1$$
$$ \Rightarrow y = 6$$
$$ \therefore $$ y coordinate of point P = 6 = height of point P above the line AC.
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