General term of the expression,

$${T_{r + 1}} = {}^n{C_r}{\left( {{3^{{1 \over 2}}}} \right)^{n - r}}{\left( {{5^{{1 \over 8}}}} \right)^r}$$

$$ = {}^n{C_r}{\left( 3 \right)^{{{n - r} \over 2}}}{\left( 5 \right)^{{r \over 8}}}$$

We will get integral term when $${{n - r} \over 2}$$ and $${r \over 8}$$ are integer

$$ \therefore $$ (1) n $$-$$ r is multiple of 2

$$ \Rightarrow $$ n $$-$$ r = 0, 2, 4, ......

(2) r is multiple of 8

$$ \Rightarrow $$ r = 0, 8, 16, .......

From this two conditions common values are = 0, 8, 16, ....... which will becomes integral terms.

Given that there are 33 integral terms.

Here first integral term at 0^th position.

Second integral term at 8^th position.

$$ \therefore $$ 33^th integral term will be at = 0 + (33 $$-$$ 1)8 = 256

So, there should be at least 256 terms.