JEE MAIN - Mathematics (2020 - 3rd September Morning Slot - No. 18)
A dice is thrown two times and the sum of the
scores appearing on the die is observed to be
a multiple of 4. Then the conditional probability
that the score 4 has appeared atleast once is :
$${1 \over 8}$$
$${1 \over 9}$$
$${1 \over 4}$$
$${1 \over 3}$$
Explanation
Let A is the event for getting score a multiple
of 4.
So, A = { (1, 3), (3, 1), (2, 2), (2, 6), (6, 2), (3, 5), (5, 3), (4, 4), (6, 6) } = 09
n(A) = 9
B : Score of 4 has appeared at least once.
B = {(4, 4)}
So, Required probability = $${1 \over 9}$$
So, A = { (1, 3), (3, 1), (2, 2), (2, 6), (6, 2), (3, 5), (5, 3), (4, 4), (6, 6) } = 09
n(A) = 9
B : Score of 4 has appeared at least once.
B = {(4, 4)}
So, Required probability = $${1 \over 9}$$
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