JEE MAIN - Mathematics (2020 - 3rd September Evening Slot - No. 3)
Let the latus ractum of the parabola y2
= 4x be
the common chord to the circles C1
and C2
each of them having radius 2$$\sqrt 5 $$. Then, the
distance between the centres of the circles C1
and C2
is :
8
12
$$8\sqrt 5 $$
$$4\sqrt 5 $$
Explanation
_3rd_September_Evening_Slot_en_3_1.png)
For parabola y2 = 4x,
Length of latus rectum = 4a = 4
C1C2 = 2(C1A)
C1A = $$\sqrt {{{(2\sqrt 5 )}^2} - {2^2}} = 4$$
$$ \therefore $$ C1C2 = 2(4) = 8
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