JEE MAIN - Mathematics (2019 - 9th January Evening Slot - No. 3)
The number of all possible positive integral values of $$\alpha $$ for which the roots of the quadratic equation, 6x2 $$-$$ 11x + $$\alpha $$ = 0 are rational numbers is :
3
2
4
5
Explanation
For rational D must be perfect square
D = 121 $$-$$ 24$$\alpha $$
for 121 $$-$$ 24$$\alpha $$ to be perfect square a must be 3, 4, 5
So, ans $$\alpha $$ = 3
D = 121 $$-$$ 24$$\alpha $$
for 121 $$-$$ 24$$\alpha $$ to be perfect square a must be 3, 4, 5
So, ans $$\alpha $$ = 3
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