JEE MAIN - Mathematics (2019 - 12th January Morning Slot - No. 18)
The area (in sq. units) of the region bounded by the parabola, y = x2 + 2 and the lines, y = x + 1, x = 0 and x = 3, is
$${{15} \over 4}$$
$${{15} \over 2}$$
$${{21} \over 2}$$
$${{17} \over 4}$$
Explanation
_12th_January_Morning_Slot_en_18_1.png)
Required area
$$ = \int\limits_0^3 {\left( {{x^2} + 2} \right)dx - {1 \over 2}.5.3 = 9 + 6 - {{15} \over 2}} {}$$
$$ = {{15} \over 2}$$
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