JEE MAIN - Mathematics (2019 - 12th January Evening Slot - No. 16)
In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the students selected has opted neither for NCC
nor for NSS is :
$${1 \over 3}$$
$${1 \over 6}$$
$${2 \over 3}$$
$${5 \over 6}$$
Explanation
_12th_January_Evening_Slot_en_16_1.png)
A $$ \to $$ opted NCC
B $$ \to $$ opted NSS
$$ \therefore $$ P (nither A nor B) $$=$$ $${{10} \over {60}} = z{1 \over 6}$$
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