JEE MAIN - Mathematics (2019 - 12th January Evening Slot - No. 12)
If a straight line passing through the point P(–3, 4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is :
x – y + 7 = 0
4x – 3y + 24 = 0
4x + 3y = 0
3x – 4y + 25 = 0
Explanation
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Let the line be $${x \over a} + {y \over b} = 1$$
($$-$$ 3, 4) = $$\left( {{a \over 2},{b \over 2}} \right)$$
a = $$-$$6, b = 8
equation of line is 4x $$-$$ 3y + 24 = 0
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