JEE MAIN - Mathematics (2019 - 12th April Morning Slot - No. 8)

If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is :

$${1 \over {10}}$$

$${3 \over {10}}$$

$${3 \over {20}}$$

$${1 \over {5}}$$

Explanation

Choosing vertices of a regular hexagon alternate, here A₁, A₃, A₅ or A₂, A₄, A₆ will result in an equilateral triangle.

Hence the required probability = $${2 \over {{}^6{C_3}}}$$ = $${1 \over {10}}$$

JEE MAIN - Mathematics (2019 - 12th April Morning Slot - No. 8)

Explanation

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