JEE MAIN - Mathematics (2019 - 12th April Morning Slot - No. 22)
The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21
are distinct, is :
220 - 1
220
220 + 1
221
Explanation
21C0 + 21C1 + 21C2 + ....... + 21C10 = $${{{2^{21}}} \over 2} = {2^{20}}$$
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