JEE MAIN - Mathematics (2019 - 12th April Morning Slot - No. 19)
If the angle of intersection at a point where the two circles with radii 5 cm and 12 cm intersect is 90o, then
the length (in cm) of their common chord is :
$${{13} \over 5}$$
$${{60} \over {13}}$$
$${{120} \over {13}}$$
$${{13} \over 2}$$
Explanation
_12th_April_Morning_Slot_en_19_1.png)
C1C2 = $$\sqrt {{{12}^2} + {5^2}} $$ = 13Area of $$\Delta $$AC1C2 = $${1 \over 2}.12.5 = {1 \over 2}.13{{AB} \over 2} \Rightarrow AB = {{120} \over {13}}units$$
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