JEE MAIN - Mathematics (2019 - 11th January Evening Slot - No. 9)
The area (in sq. units) in the first quadrant bounded by the parabola, y = x2 + 1, the tangent to it at the point (2, 5) and the coordinate axes is :
$${8 \over 3}$$
$${{14} \over 3}$$
$${{187} \over {24}}$$
$${{37} \over {24}}$$
Explanation
_11th_January_Evening_Slot_en_9_1.png)
Area $$ = \int\limits_0^2 {\left( {{x^2} + 1} \right)dx - {1 \over 2}} \left( {{5 \over 4}} \right)\left( 5 \right) = {{37} \over {24}}$$
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