JEE MAIN - Mathematics (2019 - 10th January Morning Slot - No. 11)
If the line 3x + 4y – 24 = 0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is :
(3, 4)
(2, 2)
(4, 4)
(4, 3)
Explanation
_10th_January_Morning_Slot_en_11_1.png)
$$\left| {{{3r + 4r - 24} \over 5}} \right| = r$$
$$7r - 24 = \pm 5r$$
$$2r = 24$$ or $$12r + 24$$
$$r = 14,\,\,\,r = 2$$
then incentre is $$(2,2)$$
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