JEE MAIN - Mathematics (2019 - 10th January Evening Slot - No. 3)
Let f : ($$-$$1, 1) $$ \to $$ R be a function defined by f(x) = max $$\left\{ { - \left| x \right|, - \sqrt {1 - {x^2}} } \right\}.$$ If K be the set of all points at which f is not differentiable, then K has exactly -
one element
three elements
five elements
two elements
Explanation
f : ($$-$$ 1, 1) $$ \to $$ R
f(x) = max {$$-$$ $$\left| x \right|, - \sqrt {1 - {x^2}} $$}
Non-derivable at 3 points in ($$-$$1, 1)
f(x) = max {$$-$$ $$\left| x \right|, - \sqrt {1 - {x^2}} $$}
_10th_January_Evening_Slot_en_3_1.png)
Non-derivable at 3 points in ($$-$$1, 1)
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