JEE MAIN - Mathematics (2019 - 10th April Morning Slot - No. 12)
The number of 6 digit numbers that can be formed using the digits 0, 1, 2, 5, 7 and 9 which are divisible by
11 and no digit is repeated is :
36
60
72
48
Explanation
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digit 0, 1, 2, 5, 7, 9
$$\left( {{a_1} + {a_3} + {a_5}} \right) - \left( {{a_2} + {a_4} + {a_6}} \right) = 11\,K$$
so (1, 2, 9) (0, 5, 7)
Now number of ways to arranging them
= 3! × 3! + 3! × 2 × 2
= 6 × 6 + 6 × 4
= 6 × 10
= 60
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