JEE MAIN - Mathematics (2019 - 10th April Morning Slot - No. 11)
If a1, a2, a3, ............... an are in A.P. and a1 + a4 + a7 + ........... + a16 = 114, then a1 + a6 + a11 + a16 is equal to :
38
98
76
64
Explanation
3(a1 + a16) = 114
$${a_1} + {a_{16}} = 38$$
Now a1 + a6 + a11 + a16 = 2(a1 + a16)
= 2 × 38 = 76
$${a_1} + {a_{16}} = 38$$
Now a1 + a6 + a11 + a16 = 2(a1 + a16)
= 2 × 38 = 76
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