JEE MAIN - Mathematics (2017 - 9th April Morning Slot - No. 20)
A square, of each side 2, lies above the x-axis and has one vertex at the origin. If
one of the sides passing through the origin makes an angle 30o with the positive direction of the x-axis, then the sum of the x-coordinates of the vertices of the square is :
$$2\sqrt 3 - 1$$
$$2\sqrt 3 - 2$$
$$\sqrt 3 - 2$$
$$\sqrt 3 - 1$$
Explanation
_9th_April_Morning_Slot_en_20_1.png)
Let, coordinate of point A = (x, y).
$$\therefore\,\,\,$$ For point A,
$${x \over {\cos {{30}^ \circ }}}$$ = $${y \over {\sin {{30}^ \circ }}}$$ = 2
$$ \Rightarrow $$ x = $$\sqrt 3 $$
and y = 1
Similarly, For point B,
$${x \over {\cos {{75}^ \circ }}}$$ = $${y \over {\sin {{75}^ \circ }}}$$ = 2$$\sqrt 2 $$
$$\therefore\,\,\,$$ x = $$\sqrt 3 - 1$$
y = $$\sqrt 3 + 1$$
For point C,
$${x \over {cos{{120}^ \circ }}}$$ = $${y \over {sin{{120}^ \circ }}}$$ = 2
$$ \Rightarrow $$$$\,\,\,$$ x = $$-$$1
y = $$\sqrt 3 $$
$$\therefore\,\,\,$$ Sum of the x - coordinate of the vertices
= 0 + $$\sqrt 3 $$ + $$\sqrt 3 $$ $$-$$ 1 + ($$-$$ 1) = 2$$\sqrt 3 $$ $$-$$ 2
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