JEE MAIN - Mathematics (2011 - No. 19)
These are 10 points in a plane, out of these 6 are collinear, if N is the number of triangles formed by joining these points. then:
$$N \le 100$$
$$100 < N \le 140$$
$$140 < N \le 190\,$$
$$N > 190$$
Explanation
We need 3 points to create a triangle. With 10 points number of triangle possible $${}^{10}{C_3}$$
Here 6 points are on the same line so we can't make any triangle with those 6 points.
So subtract $${}^{6}{C_3}$$.
$$\therefore$$ $$N = {}^{10}{C_3} - {}^6{C_3}$$
$$ = {{10\,.\,9\,.\,8} \over {1\,.\,2\,.\,3}} - {{6\,.\,5\,.\,4} \over {1\,.\,2\,.\,3}}$$
$$ = 120 - 20$$
$$ = 100$$
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