JEE MAIN - Mathematics (2011 - No. 19)

These are 10 points in a plane, out of these 6 are collinear, if N is the number of triangles formed by joining these points. then:
$$N \le 100$$
$$100 < N \le 140$$
$$140 < N \le 190\,$$
$$N > 190$$

Explanation

We need 3 points to create a triangle. With 10 points number of triangle possible $${}^{10}{C_3}$$

Here 6 points are on the same line so we can't make any triangle with those 6 points.

So subtract $${}^{6}{C_3}$$.

$$\therefore$$ $$N = {}^{10}{C_3} - {}^6{C_3}$$

$$ = {{10\,.\,9\,.\,8} \over {1\,.\,2\,.\,3}} - {{6\,.\,5\,.\,4} \over {1\,.\,2\,.\,3}}$$

$$ = 120 - 20$$

$$ = 100$$

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