JEE MAIN - Mathematics (2010 - No. 4)
If $$f$$has a local minimum at $$x=-1$$, then a possible value of $$k$$ is
$$0$$
$$ - {1 \over 2}$$
$$-1$$
$$1$$
Explanation
$$f\left( x \right) = \left\{ {\matrix{
{k - 2x,\,\,\,\,if\,\,\,\,x \le - 1} \cr
{2x + 3,\,\,\,\,if\,\,\,\,x > - 1} \cr
} } \right.$$
This is true where $$k=-1$$
This is true where $$k=-1$$
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