JEE MAIN - Mathematics (2002 - No. 38)
The locus of the centre of a circle which touches the circle $$\left| {z - {z_1}} \right| = a$$ and$$\left| {z - {z_2}} \right| = b\,$$ externally
($$z,\,{z_1}\,\& \,{z_2}\,$$ are complex numbers) will be :
($$z,\,{z_1}\,\& \,{z_2}\,$$ are complex numbers) will be :
an ellipse
a hyperbola
a circle
none of these
Explanation
Let the circle be $$\left| {z - {z_3}} \right| = r.$$
Then according to given conditions
$$\left| {{z_3} - {z_1}} \right| = r + a$$ (Shown in the image)
and $$\left| {{z_3} - {z_2}} \right| = r + b.$$ (Shown in the image)
Eliminating $$r,$$ we get
$$\left| {{z_3} - {z_1}} \right| - \left| {{z_3} - {z_2}} \right| = a - b.$$
$$\therefore$$ Locus of center $${z_3}$$ is
$$\left| {z - {z_1}} \right| - \left| {z - {z_2}} \right| = a - b$$ = constant.
Definition of hyperbola says, when difference of distance between two points is constant from a particular point then that particular point will lie on a hyperbola.
Here distance of z1 from z3 is = $$r + a$$ and distance of z2 from z3 is = $$r + b$$
Now their difference = ($$r + a$$) - ($$r + b$$) = $$a - b$$ = a constant
$$\therefore$$ Locus of z3 is a hyperbola.
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