Let $\mathrm{A}=\left[\begin{array}{ccc}2 & 2+p & 2+p+q \\ 4 & 6+2 p & 8+3 p+2 q \\ 6 & 12+3 p & 20+6 p+3 q\end{array}\right]$. If $\operatorname{det}(\operatorname{adj}(\operatorname{adj}(3 A)))=2^m \cdot 3^n, m, n \in \mathrm{~N}$, then $m+n$ is equal to