JEE MAIN - Mathematics Hindi (2025 - 8th April Evening Shift - No. 10)

माना $A=\left\{\theta \in[0,2 \pi]: 1+10 \operatorname{Re}\left(\frac{2 \cos \theta+i \sin \theta}{\cos \theta-3 i \sin \theta}\right)=0\right\}$ है। तो $\sum_\limits{\theta \in \mathrm{A}} \theta^2$ बराबर हे
$\frac{21}{4} \pi^2$
$6 \pi^2$
$\frac{27}{4} \pi^2$
$8 \pi^2$

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