JEE MAIN - Mathematics Hindi (2025 - 29th January Morning Shift - No. 10)

$\lim \limits_{n \rightarrow \infty}\left(\sum\limits_{k=1}^n \frac{k^3+6 k^2+11 k+5}{(k+3)!}\right)$ का मान है :
5/3
2
4/3
7/3

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