JEE MAIN - Mathematics Hindi (2025 - 28th January Morning Shift - No. 7)
यदि $\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{96 x^2 \cos ^2 x}{\left(1+e^x\right)} \mathrm{d} x=\pi\left(\alpha \pi^2+\beta\right), \alpha, \beta \in \mathbb{Z}$, तब $(\alpha+\beta)^2$ का मान है
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