JEE MAIN - Mathematics Hindi (2025 - 24th January Morning Shift - No. 7)

यदि $\alpha$ और $\beta$ समीकरण के मूल हैं $2 z^2-3 z-2 i=0$, जहां $i=\sqrt{-1}$, तब $16 \cdot \operatorname{Re}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) \cdot \operatorname{lm}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right)$ के बराबर है
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