JEE MAIN - Mathematics Hindi (2025 - 24th January Evening Shift - No. 7)
यदि $\alpha>\beta>\gamma>0$, तो अभिव्यक्ति $\cot ^{-1}\left\{\beta+\frac{\left(1+\beta^2\right)}{(\alpha-\beta)}\right\}+\cot ^{-1}\left\{\gamma+\frac{\left(1+\gamma^2\right)}{(\beta-\gamma)}\right\}+\cot ^{-1}\left\{\alpha+\frac{\left(1+\alpha^2\right)}{(\gamma-\alpha)}\right\}$ किसके बराबर है:
$3 \pi$
$\frac{\pi}{2}-(\alpha+\beta+\gamma)$
$\pi$
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