JEE MAIN - Mathematics Hindi (2025 - 24th January Evening Shift - No. 6)
कुछ $a, b$ के लिए, $f(x)=\left|\begin{array}{ccc}\mathrm{a}+\frac{\sin x}{x} & 1 & \mathrm{~b} \\ \mathrm{a} & 1+\frac{\sin x}{x} & \mathrm{~b} \\ \mathrm{a} & 1 & \mathrm{~b}+\frac{\sin x}{x}\end{array}\right|, x \neq 0, \lim _{x \rightarrow 0} f(x)=\lambda+\mu \mathrm{a}+\nu \mathrm{b}.$ तो $(\lambda+\mu+v)^2$ निम्नलिखित के बराबर है:
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