JEE MAIN - Mathematics Hindi (2025 - 23rd January Morning Shift - No. 6)
यदि $\frac{\pi}{2} \leq x \leq \frac{3 \pi}{4}$, तो $\cos ^{-1}\left(\frac{12}{13} \cos x+\frac{5}{13} \sin x\right)$ बराबर है
$x+\tan ^{-1} \frac{5}{12}$
$x-\tan ^{-1} \frac{4}{3}$
$x+\tan ^{-1} \frac{4}{5}$
$x-\tan ^{-1} \frac{5}{12}$
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