JEE MAIN - Mathematics Hindi (2025 - 22nd January Morning Shift - No. 20)
यदि $\sum_\limits{r=1}^n T_r=\frac{(2 n-1)(2 n+1)(2 n+3)(2 n+5)}{64}$, तो $\lim _\limits{n \rightarrow \infty} \sum_\limits{r=1}^n\left(\frac{1}{T_r}\right)$ के बराबर है:
$\frac{2}{3}$
$\frac{1}{3}$
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