JEE MAIN - Mathematics Hindi (2024 - 6th April Morning Shift - No. 8)
यदि $$f(x)=\left\{\begin{array}{ll}x^3 \sin \left(\frac{1}{x}\right), & x \neq 0 \\ 0 & , x=0\end{array}\right.$$, तो
$$f^{\prime \prime}(0)=0$$
$$f^{\prime \prime}(0)=1$$
$$f^{\prime \prime}\left(\frac{2}{\pi}\right)=\frac{24-\pi^2}{2 \pi}$$
$$f^{\prime \prime}\left(\frac{2}{\pi}\right)=\frac{12-\pi^2}{2 \pi}$$
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