JEE MAIN - Mathematics Hindi (2024 - 6th April Morning Shift - No. 12)

$$\alpha, \beta \in \mathbb{R}$$ और प्राकृतिक संख्या $$n$$ के लिए, माना $$A_r=\left|\begin{array}{ccc}r & 1 & \frac{n^2}{2}+\alpha \\ 2 r & 2 & n^2-\beta \\ 3 r-2 & 3 & \frac{n(3 n-1)}{2}\end{array}\right|$$, तो $$2 A_{10}-A_8$$ है
$$4 \alpha+2 \beta$$
0
$$2 n$$
$$2 \alpha+4 \beta$$

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