JEE MAIN - Mathematics Hindi (2024 - 6th April Evening Shift - No. 5)
$$\lim _\limits{n \rightarrow \infty} \frac{\left(1^2-1\right)(n-1)+\left(2^2-2\right)(n-2)+\cdots+\left((n-1)^2-(n-1)\right) \cdot 1}{\left(1^3+2^3+\cdots \cdots+n^3\right)-\left(1^2+2^2+\cdots \cdots+n^2\right)}$$ बराबर है :
$$\frac{2}{3}$$
$$\frac{1}{2}$$
$$\frac{3}{4}$$
$$\frac{1}{3}$$
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