JEE MAIN - Mathematics Hindi (2024 - 5th April Morning Shift - No. 12)

यदि $$\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\ldots+\frac{1}{\sqrt{99}+\sqrt{100}}=m$$ और $$\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\ldots+\frac{1}{99 \cdot 100}=\mathrm{n}$$, तो बिंदु $$(\mathrm{m}, \mathrm{n})$$ रेखा पर स्थित है
$$11(x-1)-100 y=0$$
$$11 x-100 y=0$$
$$11(x-1)-100(y-2)=0$$
$$11(x-2)-100(y-1)=0$$

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