JEE MAIN - Mathematics Hindi (2024 - 4th April Morning Shift - No. 18)

यदि समीकरण निकाय

$$\begin{aligned} & x+(\sqrt{2} \sin \alpha) y+(\sqrt{2} \cos \alpha) z=0 \\ & x+(\cos \alpha) y+(\sin \alpha) z=0 \\ & x+(\sin \alpha) y-(\cos \alpha) z=0 \end{aligned}$$

का अतुच्छ हल है, तो $$\alpha \in\left(0, \frac{\pi}{2}\right)$$ बराबर है :

$$\frac{5 \pi}{24}$$
$$\frac{11 \pi}{24}$$
$$\frac{7 \pi}{24}$$
$$\frac{3 \pi}{4}$$

Comments (0)

Advertisement