JEE MAIN - Mathematics Hindi (2024 - 4th April Evening Shift - No. 3)
$$\frac{1 \times 2^2+2 \times 3^2+\ldots .+100 \times(101)^2}{1^2 \times 2+2^2 \times 3+\ldots+100^2 \times 101}$$ का मान है
$$\frac{305}{301}$$
$$\frac{306}{305}$$
$$\frac{32}{31}$$
$$\frac{31}{30}$$
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