JEE MAIN - Mathematics Hindi (2024 - 30th January Morning Shift - No. 30)
यदि फलन
$$f(x)= \begin{cases}\frac{1}{|x|}, & |x| \geqslant 2 \\ a x^2+2 b, & |x|<2\end{cases}$$
$$\mathrm{R}$$ पर अवकलनीय है, तो $$48(\mathrm{a}+\mathrm{b})$$ बराबर है __________ |
Answer
15
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