JEE MAIN - Mathematics Hindi (2024 - 29th January Morning Shift - No. 4)
यदि समीकरण $$4 \cos \theta+5 \sin \theta=1$$ का हल $$\alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2}$$ हे, तो $$\tan \alpha$$ का मान है
$$\frac{10-\sqrt{10}}{12}$$
$$\frac{\sqrt{10}-10}{6}$$
$$\frac{\sqrt{10}-10}{12}$$
$$\frac{10-\sqrt{10}}{6}$$
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