JEE MAIN - Mathematics Hindi (2024 - 29th January Morning Shift - No. 18)

$$\mathop {\lim }\limits_{x \to {\pi \over 2}} \left( {{1 \over {{{\left( {x - {\pi \over 2}} \right)}^2}}}\int\limits_{{x^3}}^{{{\left( {{\pi \over 2}} \right)}^3}} {\cos \left( {{t^{{1 \over 3}}}} \right)dt} } \right)$$ बराबर है
$$\frac{3 \pi^2}{4}$$
$$\frac{3 \pi^2}{8}$$
$$\frac{3 \pi}{4}$$
$$\frac{3 \pi}{8}$$

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