JEE MAIN - Mathematics Hindi (2023 - 6th April Morning Shift - No. 7)
माना $$5 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x>0$$ है। तब $$18 \int_\limits1^2 f(x) d x$$ का मान है :
$$10 \log _e 2+6$$
$$5 \log _e 2-3$$
$$10 \log _e 2-6$$
$$5 \log _e 2+3$$
Comments (0)
