JEE MAIN - Mathematics Hindi (2023 - 6th April Evening Shift - No. 9)

$$\lim _\limits{n \rightarrow \infty}\left\{\left(2^{\frac{1}{2}}-2^{\frac{1}{3}}\right)\left(2^{\frac{1}{2}}-2^{\frac{1}{5}}\right) \ldots . .\left(2^{\frac{1}{2}}-2^{\frac{1}{2 n+1}}\right)\right\}$$ बराबर है:
$$\sqrt2$$
$$1$$
$$\frac{1}{\sqrt2}$$
$$0$$

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