JEE MAIN - Mathematics Hindi (2023 - 25th January Evening Shift - No. 5)
यदि फलन $$f(x)=\left\{\begin{array}{cl}(1+|\cos x|)^ \frac{\lambda}{|\cos x|} & , 0 < x < \frac{\pi}{2} \\ \mu & , \quad x=\frac{\pi}{2} \\ e^\frac{\cot 6 x}{{\cot 4 x}} &, \frac{\pi}{2} < x < \pi\end{array}\right.$$
$$x=\frac{\pi}{2}$$ पर संतत है, तो $$9 \lambda+6 \log _{\mathrm{e}} \mu+\mu^{6}-\mathrm{e}^{6 \lambda}$$ बराबर है
11
10
8
$$\mathrm{2e^4+8}$$
Comments (0)
