JEE MAIN - Mathematics Hindi (2023 - 25th January Evening Shift - No. 15)

माना $$A=\left[\begin{array}{cc} \frac{1}{\sqrt{10}} & \frac{3}{\sqrt{10}} \\ \frac{-3}{\sqrt{10}} & \frac{1}{\sqrt{10}} \end{array}\right]$$ तथा $$B=\left[\begin{array}{cc} 1 & -i \\ 0 & 1 \end{array}\right]$$ है, जहाँ $$i=\sqrt{-1}$$ है। यदि $$\mathrm{M}=\mathrm{A}^{\mathrm{T}} \mathrm{B} \mathrm{A}$$ है, तो आव्यूह $$\mathrm{AM}^{2023} \mathrm{~A}^{\mathrm{T}}$$ का व्युत्क्रम है
$$\left[\begin{array}{cc}1 & -2023 i \\ 0 & 1\end{array}\right]$$
$$\left[\begin{array}{cc}1 & 0 \\ 2023 i & 1\end{array}\right]$$
$$\left[\begin{array}{cc}1 & 2023 i \\ 0 & 1\end{array}\right]$$
$$\left[\begin{array}{cc}1 & 0 \\ -2023 i & 1\end{array}\right]$$

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