JEE MAIN - Mathematics Hindi (2023 - 24th January Morning Shift - No. 4)
$$\mathop {\lim }\limits_{t \to 0} {\left( {{1^{{1 \over {{{\sin }^2}t}}}} + {2^{{1 \over {{{\sin }^2}t}}}}\, + \,...\, + \,{n^{{1 \over {{{\sin }^2}t}}}}} \right)^{{{\sin }^2}t}}$$ बराबर है
$$\frac{n(n+1)}{2}$$
$$\mathrm{n}$$
$$\mathrm{n}^{2}+\mathrm{n}$$
$$\mathrm{n}^{2}$$
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