JEE MAIN - Mathematics Hindi (2023 - 24th January Evening Shift - No. 12)
$$\left(\frac{1+\sin \frac{2 \pi}{9}+i \cos \frac{2 \pi}{9}}{1+\sin \frac{2 \pi}{9}-i \cos \frac{2 \pi}{9}}\right)^3$$ का मान है:
$$ - {1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
$$ - {1 \over 2}\left( {\sqrt 3 - i} \right)$$
$${1 \over 2}\left( {1 - i\sqrt 3 } \right)$$
$${1 \over 2}\left( {\sqrt 3 + i} \right)$$
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