JEE MAIN - Mathematics Hindi (2023 - 1st February Morning Shift - No. 13)
यदि अवकल समीकरण $$\frac{d y}{d x}+y \tan x=x \sec x, 0 \leq x \leq \frac{\pi}{3}, y(0)=1$$ का हल वक्र $$y=y(x)$$ है, तो $$y\left(\frac{\pi}{6}\right)$$ का मान है:
$${\pi \over {12}} - {{\sqrt 3 } \over 2}{\log _e}\left( {{{2\sqrt 3 } \over e}} \right)$$
$${\pi \over {12}} + {{\sqrt 3 } \over 2}{\log _e}\left( {{{2\sqrt 3 } \over e}} \right)$$
$${\pi \over {12}} + {{\sqrt 3 } \over 2}{\log _e}\left( {{2 \over {e\sqrt 3 }}} \right)$$
$${\pi \over {12}} - {{\sqrt 3 } \over 2}{\log _e}\left( {{2 \over {e\sqrt 3 }}} \right)$$
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