JEE MAIN - Mathematics Hindi (2023 - 1st February Evening Shift - No. 16)

माना अवकल समीकरण $$2 x^{2} y \mathrm{~d} y-\left(1-x y^{2}\right) \mathrm{d} x=0, x > 0, y(2)=\sqrt{\log _{e} 2}$$ का हल $$\alpha x=\exp \left(x^{\beta} y^{\gamma}\right)$$ है । तो $$\alpha+\beta-\lambda$$ बराबर है :
1
0
3
$$-$$1

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